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% !TeX encoding = UTF-8
% !TeX spellcheck = sl_SI
\documentclass[]{article}
\usepackage[utf8]{inputenc}
\usepackage{etoolbox}
\usepackage[hidelinks]{hyperref}
\usepackage[a4paper, total={7in, 10in}]{geometry}
\usepackage{graphicx}
\usepackage{hologo}
\usepackage{amssymb}
\usepackage{pgfplots}
\usepackage[inline]{enumitem}
\usepackage{amsmath}
\usepackage{siunitx}
\usepackage{multicol}
\usepackage{tabularcalc}
\usepackage{amsmath}
\usepackage{float}
\usepackage{tasks}
\usepackage{filecontents}
\usepackage{textcomp}
\usepackage{tkz-euclide}
\usepackage{listings}
% \usepackage{multienum} % weird with labels
\usetikzlibrary{calc} %% not really needed............. idk.
%\usetikzlibrary{external}
% \usetkzobj{all} % tkz-euclide > 3.02 tega ne potrebuje več (:
%\tikzexternalize
\usepackage{xcolor}
\sisetup{output-decimal-marker = {,}, quotient-mode=fraction,per-mode=fraction} % per-mode=symbol
\newcommand\ddfrac[2]{\frac{\displaystyle #1}{\displaystyle #2}}
\newcommand{\functionSamples}{100} % fix to fancier value upon release, keep low during development
\newcommand{\razhroscevanje}{0}
\definecolor{codegreen}{rgb}{0,0.6,0}
\definecolor{codegray}{rgb}{0.5,0.5,0.5}
\definecolor{codepurple}{rgb}{0.58,0,0.82}
\definecolor{backcolour}{rgb}{0.95,0.95,0.92}

\lstdefinestyle{mystyle}{
    backgroundcolor=\color{backcolour},   
    commentstyle=\color{codegreen},
    keywordstyle=\color{magenta},
    numberstyle=\tiny\color{codegray},
    stringstyle=\color{codepurple},
    basicstyle=\ttfamily\footnotesize,
    breakatwhitespace=false,         
    breaklines=true,                 
    captionpos=b,                    
    keepspaces=true,                 
    numbers=left,                    
    numbersep=5pt,                  
    showspaces=false,                
    showstringspaces=false,
    showtabs=false,                  
    tabsize=2
}

\lstset{style=mystyle}
\def\@maketitle{%
	\newpage
	\null
	\vskip 2em%
	\begin{center}%
		\let \footnote \thanks
		{\LARGE \@title \par}%
		\vskip 1.5em%
		{\large
			\lineskip .5em%
			\begin{tabular}[t]{c}% <------
				\@author%            <------ Authors
			\end{tabular}\par}%    <------
		\vskip 1em%
		{\large \@date}%
	\end{center}%
	\par
	\vskip 1.5em}
%opening
\makeatletter
\newcommand{\stevilkadn}{6}
\newcommand{\snovdn}{Skladnost trikotnikov }
\newcommand{\cm}[1]{\SI{#1}{\centi\meter}}
\newcommand{\xslalph}[1]{\expandafter\@xslalph\csname c@#1\endcsname}
\newcommand{\@xslalph}[1]{%
	\ifcase#1\or a\or b\or c\or \v{c}\or d\or e\or f\or g\or h\or i%
	\or j\or k\or l\or m\or n\or o\or p\or r\or s\or \v{s}%
	\or t\or u\or v\or z\or \v{z}
	\else\@ctrerr\fi%
}
\AddEnumerateCounter{\xslalph}{\@xslalph}{m}
\makeatother
\newcommand\gauss[2]{1/(#2*sqrt(2*pi))*exp(-((x-#1)^2)/(2*#2^2))} % Gauss function, parameters mu and sigma
\newcommand*\textfrac[2]{
	\frac{\text{#1}}{\text{#2}}
}
\renewcommand\abstractname{Povzetek}
\date{17. september 2020}
\renewcommand\contentsname{Kazalo vsebine}
\renewcommand\figurename{Slika}
\renewcommand\abstractname{Povzetek}
\newcommand{\iic}{I\textsuperscript{2}C }
% \patchcmd{\thebibliography}{\section*{\refname}}{}{}{}
\title{%
	\snovdn --- \stevilkadn. domača naloga \\
	\large Matematika, Gimnazija Bežigrad}
\author{\begin{tabular}{rl}
		\textbf{Profesor:} & prof. Vilko Domajnko \\
		\textbf{Avtor:} & Anton Luka Šijanec, 2. a
%		\textbf{Avtor:} & Anton Luka Šijanec \\ & Member 2 \\ & Member 3
\end{tabular}}


% \everymath{\displaystyle} % https://tex.stackexchange.com/a/32847/212260
\begin{document}
\maketitle

\begin{abstract}
	Ta dokument obsega naloge, naročene dijakom 16. septembra 2020, in njihove
	rešitve, ki sem jih spisal sam. Naloge obsegajo snov \textit{\snovdn}in so
	iz učbenika in vaj/zbirke nalog.
\end{abstract}
% \tableofcontents

\section{Učbenik \textit{Matematika 1}: Stran 19}
\begin{enumerate}[label=\textbf{\arabic*.}]
	\item Načrtaj kote, velike \ang[parse-numbers=false]{\textbf{105}}, \ang{150}, \ang{15}, \ang{135} in \ang{165}.
		\begin{center}
			\begin{tikzpicture}
				\tkzDefPoint(-5,0){A} %%% kot 90 stopinj ˇˇˇ
				\tkzDefPoint(5,0){B}
				\tkzDefPoint(0,0){CHEATING0} \tkzDefPoint(0.05,0){CHEATING1} \tkzDefPoint(-0.05,0){CHEATING2}
				\tkzInterCC(A,B)(B,A) \tkzGetPoints{C}{D}
				\tkzDrawPoints(A) \tkzCompass(A,C) \tkzCompass(B,C) \tkzCompass(A,CHEATING1) \tkzCompass(B,CHEATING2) \tkzCompass(A,B)
				\tkzDrawLine(A,B) \tkzDrawLine(CHEATING0,C) \tkzMarkAngle[mark=none](B,CHEATING0,C)
				\tkzMarkRightAngles(B,CHEATING0,C)
				%%% kot 60 stopinj ˇˇˇ
				\tkzInterLC(CHEATING0,C)(CHEATING0,A) \tkzGetPoints{E}{F} \tkzCompass(CHEATING0,F)
				\tkzInterCC(CHEATING0,F)(F,CHEATING0) \tkzGetPoints{G}{H} \tkzCompass(CHEATING0,G) \tkzCompass(F,G)
				\tkzDrawLine(CHEATING0,G) \tkzMarkAngle[color=magenta, mark=none](F,CHEATING0,G)
				%%% kot 60/2 stopinj ˇˇˇ
				\tkzDrawLine(F,G) \tkzDefMidPoint(F,G) \tkzGetPoint{I} \tkzCompass(F,I) \tkzCompass(G,I)
				\tkzMarkAngle[color=cyan,mark=none, size=1.1cm](F,CHEATING0,I)
				%%% kot 60/2/2 stopinj = 15 stopinj ˇˇˇ
				\tkzDefMidPoint(F,I) \tkzGetPoint{J} \tkzCompass(F,J) \tkzCompass(I,J)
				\tkzMarkAngle[color=yellow,mark=none, size=1.2cm](F,CHEATING0,J)
				%%% kot 105 stopinj = kot 90 stopinj + kot 15 stopinj ˇˇˇ
				\tkzMarkAngle[color=red,mark=none, size=0.9cm](B,CHEATING0,J) \tkzDrawLine(CHEATING0,J)
			\end{tikzpicture}
		\end{center}
	\item Načrtaj trikotnik, ki ima stranice dolge \SI{6}{\centi\meter}, \SI{4}{\centi\meter} in \SI{4,5}{\centi\meter}.

	\item Načrtaj trikotnik z danimi podatki.
		\begin{multicols}{4}
			\noindent
			\begin{enumerate}[label=\textbf{\xslalph*)}]
				\item	$\mathbf{c=}\SI[parse-numbers=false, parse-units=false]{\mathbf{5}}{\mathbf{\centi\meter}}$

							$\mathbf{b=}\SI[parse-numbers=false, parse-units=false]{\mathbf{4}}{\mathbf{\centi\meter}}$

							$\mathbf{\alpha=}\ang[parse-numbers=false, parse-units=false]{\mathbf{75}}$
				\item $a=\SI{6}{\centi\meter}$

							$\beta=\ang{60}$

							$\gamma=\ang{45}$
				\item $c=\SI{5,5}{\centi\meter}$

							$a=\SI{4}{\centi\meter}$

							$\gamma=\ang{75}$
				\item	$b=\SI{5}{\cm}$

							$c=\SI{6,5}{\centi\meter}$

							$\beta=\ang{60}$
			\end{enumerate}
		\end{multicols}
		\begin{multicols}{2}
			\noindent
			\begin{center}
				\begin{tikzpicture}
					\tkzDefPoint(0,0){A}
					\tkzDefPoint(5,0){B}
					\tkzDefPoint(4,0){b}
					\tkzDrawPoints(A) \tkzCompass(A,b) \tkzDrawLine(A,B) \tkzCompass(A,b)
					\tkzDrawSegment[dim={$\SI{4,0}{\centi\meter}$,6pt,transform shape}](A,b)
					\tkzInterCC(A,b)(b,A) \tkzGetPoints{D}{d} \tkzCompass(A,D) \tkzCompass(B,D) \tkzInterCC(D,A)(A,D)	\tkzGetPoints{e}{E}
					\tkzCompass(A,E) \tkzCompass(D,E) \tkzDefMidPoint(E,D) \tkzGetPoint{F} \tkzCompass(D,F) \tkzCompass(E,F)
					\tkzDefMidPoint(F,D) \tkzGetPoint{C} \tkzCompass(F,C) \tkzCompass(D,C) \tkzDrawLine(A,C) \tkzDrawLine(B,C)
					\tkzLabelLine[below left](B,C){$a$} \tkzLabelLine[below right](C,A){$b$} \tkzLabelLine[below](A,B){$c$}
					\tkzLabelPoints(A) \tkzLabelPoints[below left](B) \tkzLabelPoints[above right](C)
					\tkzMarkAngle[mark=none](B,A,C) \tkzLabelAngle[pos=1.2](B,A,C){$\alpha$}
				\end{tikzpicture}
				\begin{tikzpicture}
					\tkzDefPoint(0,0){A}
					\tkzDefPoint(6,0){B}
					\tkzDefPoint(4,0){a}
					\tkzDefPoint(4.5+6,0){b}
					\tkzDrawPoint(A)
					\tkzCompass(A,B)
					\tkzInterCC(A,a)(B,b) \tkzGetPoints{C}{c} \tkzCompass(A,C) \tkzCompass(B,C)
					\tkzDrawLine(A,B) \tkzDrawLine(B,C) \tkzDrawLine(C,A)
				\end{tikzpicture}
			\end{center}
		\end{multicols}
	\item Načrtaj štirikotnik z danimi podatki. Pomagaj si s trikotnika, na katera diagonala razdeli štirikotnik
		\begin{multicols}{6}
			\noindent
			\begin{enumerate}[label=\textbf{\xslalph*)}]
				\item $\mathbf{a=}\SI[parse-numbers=false, parse-units=false]{\mathbf{5}}{\mathbf{\centi\meter}}$

							$\mathbf{b=}\SI[parse-numbers=false, parse-units=false]{\mathbf{3}}{\mathbf{\centi\meter}}$

							$\mathbf{c=}\SI[parse-numbers=false, parse-units=false]{\mathbf{4}}{\mathbf{\centi\meter}}$

							$\mathbf{d=}\SI[parse-numbers=false, parse-units=false]{\mathbf{4}}{\mathbf{\centi\meter}}$

							$\mathbf{f=}\SI[parse-numbers=false, parse-units=false]{\mathbf{5}}{\mathbf{\centi\meter}}$
				\item	$a=\SI{6}{\centi\meter}$
				
							$b=\SI{5}{\centi\meter}$

							$d=\SI{4}{\centi\meter}$

							$\alpha=\ang{120}$

							$\delta=\ang{90}$
				\item	$b=\SI{6}{\centi\meter}$

							$c=\cm{2}$

							$d=\cm{5}$

							$\gamma=\ang{105}$

							$\delta=\ang{75}$
				\item	$a=\cm{7}$

							$b=\cm{4}$

							$c=\cm{5}$

							$e=\cm{6}$

							$f=\cm{5,5}$
				\item	$d=c=\cm{3}$
				
							$a=d=\cm{5}$

							$f=\cm{5,5}$
				\item $a=\cm{5}$

							$d=\cm{4}$

							$e=\cm{6}$

							$f=\cm{7}$

							$\beta=\ang{60}$
			\end{enumerate}
		\end{multicols}
		% \begin{center}
			Štirikotnikov še nismo definirali. (-; Problem je v tem, da ne vem, med katerimi pari točk so določene stranice.
		% \end{center}
\end{enumerate}

\section{Zbirka nalog \textit{Matematika 1}: Stran 16}
\begin{enumerate}[label=\textbf{\arabic*.}]
	\setcounter{enumi}{71}
	\item Trikotnika $ABC$ in $A'B'C$ sta skladna. Točki $D$ in $D'$ ležita na stranicah $AB$ oziroma $A'B'$ tako, da sta kota $DCB$ in $D'C'B'$ skladna. Dokaži, da je $|AD|=|A'D'|$
	\item Na sliki je $|AE|=|BG|$, kota $BAC$ in $FEG$ sta skladna, prav tako sta skladna kota $CBA$ in $EGF$. Dokaži, da sta trikotnika $ABC$ in $EGF$ skladna.
	\item Točke $A, B, C, E$ in $F$ ležijo, kot kaže slika: $|AB|=|BC|, AF \bot BE, CE \bot BF$. Dokaži, da je $|AF|=|CE|$.
		\begin{multicols}{2}
			\begin{center}
				\begin{tikzpicture}
					\tkzDefPoint(0,0){B}
					\tkzDefPoint(-5,0){C}
					\tkzDefPoint(210:5){A}
					%\tkzDefPoint(210:6){E}
					\tkzDefLine[orthogonal=through A](B,A) \tkzGetPoint{f}
					\tkzInterLL(A,f)(B,C)
					\tkzGetPoint{F}
					\tkzDefMidPoint(A,F) \tkzGetPoint{M}
					\tkzDefLine[orthogonal=through M](B,F) \tkzGetPoint{e}
					\tkzInterLL(C,e)(B,A) \tkzGetPoint{E}
					\tkzDrawPoints(A,B,C,F,E)
					\tkzLabelPoints(B,E,A) \tkzLabelPoints[above right](F,C)
					\tkzDrawLine(B,F)	\tkzDrawLine[add = 0 and 0](C,E)
					\tkzDrawLine(B,E)	\tkzDrawLine[add = 0 and 0](A,F)
					\tkzMarkSegments[mark=|](C,B A,B) \tkzMarkSegments[mark=||](F,A E,C)
					\tkzMarkAngles[mark=|||](C,B,A) \tkzLabelAngle[pos=2](C,B,A){$\beta$}
					\tkzMarkRightAngles(B,A,F E,C,B)
				\end{tikzpicture}
			\end{center}
			
			Trikotnika $ABF$ in $EBC$ sta skladna zaradi dveh skladnih kotov in ene stranice, zato so vse njune stranice enako dolge.
		\end{multicols}
\end{enumerate}

\section{Zaključek}
Ta dokument je informativne narave in se lahko še spreminja. Najnovejša različica, torej PDFji in
\hologo{LaTeX}
izvorna koda, zgodovina sprememb in prejšnje različice, je na voljo mojem šolskem Git repozitoriju na
\url{https://github.com/sijanec/sola-gimb-2} v mapi 
\href{https://github.com/sijanec/sola-gimb-2/tree/master/mat/domace_naloge/\stevilkadn/}{/mat/domace\_naloge/\stevilkadn/}. Povezava za ogled zadnje različice tega dokumenta v PDF obliki je  \url{http://razor.arnes.si/~asija3/files/sola/gimb/2/mat/domace_naloge/\stevilkadn/dokument.pdf} in/ali \url{https://github.com/sijanec/sola-gimb-2/raw/master/mat/domace_naloge/\stevilkadn/dokument.pdf}.

\if\razhroscevanje1
\section{Razhroščevalne informacije}
Te informacije so generirane, ker je omogočeno razhroščevanje. Prej objavo dokumenta izklopite razhroščevanje. To naredite tako, da nastavite ukaz \texttt{razhroscevanje} na 0 v začetku dokumenta.

Grafi imajo natančnost \functionSamples\space točk na graf.

Konec generiranja dokumenta: \input|"date -Ins"
\fi
%	\item $$$$
\end{document}